Step: 1

The length of PQ = 20 units.

Step: 2

PR = (3 4 )(PQ)

Step: 3

PR = (3 4 )(20) = 3 x 5 = 15

Step: 4

RQ = PQ - PR = 20 - 15 = 5

[Substitute PQ = 20 and PR = 15]

Step: 5

PR = 15 units and RQ = 5 units.

Correct Answer is : 15 units and 5 units

Step: 1

A ray is a part of a line. It has one end point and any number of points on one side of the end point.

Step: 2

A ray is named by the end point and any other point on the ray.

Step: 3

The rays in the figure, with Q as the end point are QP → , QR → and QS → .

Step: 4

The rays in the figure, with P as the end point are PQ → and PR → .

Step: 5

The rays in the figure, with R as the end point are RQ → and RP → .

Step: 6

The rays in the figure, with S as the end point are SQ → and ST → .

Step: 7

The ray in the figure, with T as the end point is TS → .

Step: 8

So, the total number of rays in the figure is 10.

[3 + 2 + 2 + 2 + 1 = 10.]

Correct Answer is : 10

Step: 1

'If the points lie on the same line, then the points are called collinear points.'

Step: 2

From the figure, B , C and D lie on the same line.

Step: 3

So, B , C and D are the three collinear points.

Correct Answer is : B , C , D

Step: 1

Let P, Q, R, S and T be the five non-collinear points.

Step: 2

Join PQ ¯ , QR ¯ , RS ¯ , ST ¯ , TP ¯ , PR ¯ , PS ¯ , QT ¯ , QS ¯ and RT ¯ as shown in the figure.

Step: 3

So, the number of segments that can be drawn using five non-collinear points is 10.

Correct Answer is : 10

Step: 1

A line segment is a part of a line. It is made up of two points and all the points of the line that joins the two points.

Step: 2

In the figure, PQ ¯ , QR ¯ , RS ¯ , PR ¯ , QS ¯ and PS ¯ are the line segments.

Step: 3

So, the number of line segments in the figure is 6.

Correct Answer is : 6

Step: 1

Let A, B, C, D, E and F be the six non-collinear points.

Step: 2

Join AB ¯ , BC ¯ , CD ¯ , DE ¯ , EF ¯ , FA ¯ , AC ¯ , AD ¯ , AE ¯ , BD ¯ , BE ¯ , BF ¯ , CE ¯ , CF ¯ and DF ¯ as shown in the figure.

Step: 3

So, the number of segments that can be drawn using six non-collinear points is 15.

Correct Answer is : 15

Step: 1

A line segment is a part of a line having exactly two end points.

Step: 2

The line segments in the figure are PR ¯ , QR ¯ , RS ¯ , ST ¯ , QS ¯ , RT ¯ , and QT ¯ .

[Identify the parts of line with exactly two end points.]

Step: 3

So, there are 7 segments in the figure.

Correct Answer is : 7

Step: 1

A line segment is a line or part of a line having exactly two end points.

Step: 2

The line segments in the figure are AB, BC, CD, DE, EF, and FA.

Step: 3

Therefore, there are 6 line segments in the given figure.

Correct Answer is : 6

- Parallel Lines and Transversals-Geometry-Solved Examples
- Angle Sum Theorem and Medians in a Triangle-Geometry-Solved Examples
- Properties of Isosceles Triangles-Geometry-Solved Examples
- Proving Quadrilateral is a Parallelogram-Geometry-Solved Examples
- ASA and AAS Postulates -Triangle Congruence-Geometry-Solved Examples
- SSS and SAS Postulates-Triangle Congruence-Geometry-Solved Examples
- Transformations-Reflections-Geometry-Solved Examples
- Transformations-Rotations-Geometry-Solved Examples
- Transformations-Translations-Geometry-Solved Examples

- Angle
- Line
- Line Segment
- Plane
- Ray