Choose values for x.

Plot the points on a graph.

The above graph matches with the Graph 2.

So, Graph 2 is the correct answer.

y = - 3x + 1

The slope is - 3 and y-intercept is 1.

Plot the point (0, b) when b is 1.

Use the slope to locate a second point on line.

m = - 31 = riserun → move 3 units downmove 1 unit right

Draw a line through the two points.

Graph of the equation y = - 3x + 1 matches with Graph 2.

x - 3y = - 6 ⇒ y = x3 + 2

The slope is 13 and y-intercept is 2.

Plot the point (0, 2).

From (0, 2), move 1 unit up and 3 units right. You get another point (3, 3).

Draw a line through these two points.

Graph of the equation x - 3y = - 6 matches with Graph 2.

The x-coordinate is always - 2, regardless of the value of y.

The graph of the equation x = - 2 is a vertical line 2 units to the left of the y-axis as shown in the following graph.

The above graph matches with the graph 3.

y = 13x - 1

Choose values for x:

When x = 0, y = 13(0) - 1 = - 1

When x = 3, y = 13(3) - 1 = 0

When x = - 3, y = 13(- 3) - 1 = - 2

The points are, (0, - 1), (3, 0), and (- 3, - 2).

Draw a line passing through these points.

The above graph matches with Graph 2.

Calculate the values of y for certain values of x as shown in the following table.

Plot the points on the graph.

Therefore, Graph 1 represents the equation y=2x-3.

y2 = x3 - 1 ⇒ y = 23x - 2

When x = 0, y = 23 (0) - 2 = - 2

When x = 3, y = 23(3) - 2 = 0

Thus, the points (0, -2) and (3, 0) are the solutions of the equation y2 = x3 - 1.

Draw a line passing through these points.

Therefore, graph 1, represents the equation y2 = x3 - 1.

y = - 34x + 3

When x = 0, y = - 34 (0) + 3 = 3

When x = 4, y = - 34(4) + 3 = 0

Thus, the points (0, 3) and (4, 0) are the solutions of the equation y = - 34 x + 3.

Draw a line passing through these points.

Therefore, graph 1 represents the equation y = - 34x + 3.

y = - 12x

When x = 2, y = - 12 (2) = - 1

When x = - 2, y = - 12( - 2) = 1

Thus, the points (2, - 1) and ( - 2, 1) are the solutions of the equation y = - 12x.

Draw a line passing through these points.

Therefore, graph 2 represents the equation y = - 12x

y = 43x - 1

When x = 3, y = 43(3) - 1 = 3

When x = 0, y = 43(0) - 1 = - 1

Thus, the points (0, - 1) and (3, 3) are the solution of the equation y = 43x - 1.

Draw a line passing through these points.

Therefore, graph 4, represents the equation y = 43x - 1.

y = - 45 = - 0.8

The y - coordinate is always - 0.8, regardless of the value of x.

Thus, the graph of the equation y = - 0.8 is a horizontal line which is 0.8 units below the x-axis as shown in the graph.

Therefore, graph 2 represents the equation y = - 45