Write the factors for each number.
19: 1, 19
30: 1, 2, 3, 5, 6, 10, 15, 30

Select the common factors.
19: 1, 19
30: 1, 2, 3, 5, 6, 10, 15, 30

The GCF is 1, which is the only common factor.

Draw a factor tree for each number.

Identify the common factors.

The GCF of 20 and 32 is 4.

Draw a factor tree for each number.

The GCF of 24 and 40 is 8.

If a number is the GCF of any two numbers, then the two numbers are multiples of that GCF.

The two smallest numbers whose GCF is 5 are 5 and 10.

16: 1, 2, 4, 8, 16
24: 1, 2, 3, 4, 6, 8, 12, 24
32: 1, 2, 4, 8, 16, 32

The common factors are 2, 4 and 8 of which 8 is the greatest.

So the GCF is 8.

Write the factors for each number.

Select the common factors.

The HCF is 2, which is the greatest of the common factors.

The prime factorisation of 72 and 84 are:
72 = 2³ × 3²
84 = 2² × 3 × 7

H.C.F. is found by multiplying all the prime factors having the least powers.

Therefore, the H.C.F. of 72 and 84 = 2² × 3 = 12.

While using Long Division Method for finding H.C.F. of two numbers, follow these steps:
(1) Divide the larger number by the smaller number.
(2) Divide the divisor by the remainder.
(3) Repeat the process of dividing until you get remainder as 0. The divisor which gives remainder 0 is the H.C.F.

Using the long division method, we get the H.C.F. of 1824 and 2304 as follows:

In the division above, the divisor 84 gives remainder 0. Therefore, the H.C.F. of 1764 and 2604 is 84.

H.C.F. of three numbers = H.C.F. of [(H.C.F. of any two) and the third.]

First we find the H.C.F. of any two of the given numbers.

While using Long Division Method for finding H.C.F. of two numbers, follow these steps:
(1) Divide the larger number by the smaller number.
(2) Divide the divisor by the remainder.
(3) Repeat the process of dividing until you get remainder as 0. The divisor which gives remainder 0 is the H.C.F.

First, let us find the H.C.F. of 714 and1666. Using the long division method, we get the H.C.F. of 714 and 1666 as follows:

In the division above, the divisor 238 gives remainder 0. Therefore, the H.C.F. of 714 and 1666 is 238.

Repeat the same process for the remaining number and the divisor 238 which got the remainder as 0.

Using the long division method, we get the H.C.F. of 238 and 9775 as follows:

In the division above, the divisor 17 gives remainder 0. Therefore, the H.C.F. of 238 and 9775 is 17.

Hence, the H.C.F. of 714, 1666 and 9775 is 17.

The prime factorisation of 630, 576 and 1080 are:
630 = 2 × 3² × 5 × 7
576 = 2⁶ × 3²
1080 = 2³ × 3³ × 5

H.C.F. is found by multiplying all the prime factors having the least powers.

Therefore, the H.C.F. of 630, 576 and 1080 = 2 × 3² = (2 × 9) = 18.

The prime factorisation of 1965, 1755 and 1560 are:
1965 = 3 × 5 × 131
1755 = 3³ × 5 × 13
1560 = 2³ × 3 × 5 × 13

H.C.F. is found by multiplying all the prime factors having the least powers.

Therefore, the H.C.F. of 1965, 1755 and 1560 = 3 × 5 = 15.

The prime factorisation of 972 and 432 are:
972 = 2² × 3⁵
432 = 2⁴ × 3³

H.C.F. is found by multiplying all the prime factors having the least powers.

Therefore, the H.C.F. of 972 and 432. = 2² × 3³ = (4 × 27) = 108.

List all the factors of the numbers.
Factors of 7: 1 and 7
Factors of 21: 1, 3, 7 and 21

Select the common factors.
Factors of 7: 1 and 7
Factors of 21: 1, 3, 7 and 21

Among the common factors 1 and 7, the greatest common factor is 7.

Therefore, the greatest common factor of 7 and 21 is 7.

List all the factors of the numbers.
Factors of 40: 1, 2, 4, 5, 8, 10, 20 and 40
Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.

Select the common factors.
Factors of 40: 1, 2, 4, 5, 8, 10, 20 and 40.
Factors of 48: 1, 2, 4, 6, 8, 12, 16, 24 and 48

Among the common factors 1, 2, 4 and 8, the greatest common factor is 8.

Therefore, the greatest common factor of 40 and 48 is 8.

Multiplying 1 and 8, we get the value as 8.

Multiplying 2 and 8, we get the value as 16.

8 = 1, 8
16 = 1, 2, 8, 16

Select the common factors.

8 and 16 are the two smallest possible numbers with GCF 8.