Triangle Proportionality Theorem states that a line drawn parallel to any of the sides of a triangle divides the other two sides proportionally.

In the given triangle ABC, BC is the base of the triangle.
DE is drawn parallel to BC and it intersects the other two sides AB and AC at D and E respectively.
Here,
=
.
This is called triangle proportionality theorem.

A. 2.59 cm
B. 1.09 cm
C. 2.09 cm
D. 1.59 cm
Correct Answer: B
Step 1: A line drawn parallel to any of the sides of a triangle divides the other two sides proportionally.
Step 2:
=
[Proportionality Theorem.]
Step 3:
[Substitute the values.]
Step 4: 14(AP) = 3(AP) + 12 [Cross multiplication.]
Step 5: 11(AP) = 12 [Simplify.]
Step 6: AP = 1.09 [Divide by 11 on both sides.]
Step 7: The length of AP is 1.09 cm.
CCSS.MATH.CONTENT.HSG.SRT.B.4Q1: In triangle ABC, line DE is parallel to BC. If AD = 4, DB = 6, and AE = 5, what is the length of EC?
Q: What does it mean for sides to be divided proportionally?
A: It means the ratio of the segments on one side is equal to the ratio of the segments on the other side.
Q: Can this theorem be used to prove lines are parallel?
A: Yes, the converse of the theorem can be used to prove that a line is parallel to one side of a triangle if it divides the other two sides proportionally.