A logarithm to the base 'e' is called the Natural Logarithm (ln x), where 'e' is an irrational constant whose value is approximately equal to 2.71828.....
The natural logarithm of 'e' itself is 1 because e1 = e, and the natural logarithm of 1 is 0, since e0 = 1.
The natural logarithm function is the inverse function of the exponential function.
The equation 24 = e6x can be solved using natural logarithm.
Applying natural logarithm on both sides, ln 24 = ln e6x
ln 24 = ln 6x, as ln eax = ax
x ∼ 0.53
A. x ∼ 0.676
B. x ∼ 1.676
C. x ∼ 0.647
D. x ∼ 1.947
Correct Answer: A
Step 1: Consider 53x = 7(x + 1)
Step 2: Apply ln on both sides, ln 53x = ln 7(x + 1)
Step 3: 3x ln 5 = (x + 1) ln 7
Step 4: 3x
= (x + 1)
Step 5: 3x (0.827) = (x + 1)
Step 6: 2.48x = (x + 1)
Step 7: (2.48 - 1)x = 1
Step 8: 1.48 x = 1
Step 9: x ∼ 0.676
Q1: Solve for x: e^(2x) = 5
Q2: Solve for x: 5^(3x) = 7^(x+1)
Q: What is the value of 'e'?
A: 'e' is an irrational constant approximately equal to 2.71828.
Q: How do I solve equations with natural logarithms?
A: Use the properties of logarithms to isolate the variable. Remember that ln(e^x) = x and e^(ln(x)) = x.