iCoachMath.com: Examples on Position - Velocity - Acceleration Functions - Applications of Derivatives - (CT)
Search:  
Advanced Search
 
Forgot Login Details?




iCoachMath Bonanza

Enroll Today and SAVE $200! Pay just $60 and benefit from iCoachMath’s highly personalized Web Math Coaching services for 1 full academic year. Offer valid until December 31, 2009.

Solved Examples

Curriculum: Connecticut Mathematics Curriculum Framework   Click to change Curriculum

Topic: Applications of Derivatives  Click to change Topic

Lesson: Position - Velocity - Acceleration Functions  Click to change Lesson

Click on a 'View Solution' below for other questions:
ee  The displacement 'S' described by a particle in t seconds is given by S = 7t - 3t2 ft . What is the velocity of the particle at any time t?  ee View Solution
ee  The displacement S of a body in t seconds is given by S = (2t3 - 7t2 + 4t + 4) m. The instantaneous velocity of the body is
  ee
View Solution
ee  The displacement of a body with time t is related as S = ae9t - be-6t. Find the rate of change of displacement with respect to time t.  ee View Solution
ee  The displacement S (in meters) of a particle is related with time t(in seconds) as S = 8t3 + 7t2 + 4t + 5 The velocity of the particle when t = 4 sec is  ee View Solution
ee  The displacement S of a particle in time t seconds is given by S = 3t3 - 2t2 - 3t + 4 ft . What is the acceleration of the particle at time t?  ee View Solution
ee  What is the acceleration of a body at t = 3 sec whose displacement S(in metres) is related with the time as S = 6t3 - 5t2 - 3t + 3?  ee View Solution
ee  The displacement of a particle S (in metres) is related with time t (in seconds) as S = t33 -15t22 + 56t Find the acceleration of the particle when it comes to rest first time.
  ee
View Solution
ee  On a straight road, vehicle A started at a point P whose displacement (metres) function with time t (seconds) is S = 2t + 2t2. After 1sec vehicle B started from the same point P in the same direction of A. The displacement (metres) function with time t (seconds) of B is S = 4t + 8t2. What is the velocity of the vehicle B when it crosses the vehicle A?
  ee
View Solution
ee  The displacement function of a particle with time t in seconds is S = 2t3 - 6t2 + 2t + 3 ft. Find the velocity of the particle when its acceleration becomes zero.
  ee
View Solution
ee  The displacement S of a particle with respect to time t is given by S = - 2t3 + 3t. The velocity of the particle  ee View Solution
ee  The distance 'S' on a straight line traveled by a particle in time t is given by S = 3t - 4t3. What is the maximum velocity of the particle?  ee View Solution
ee  On a straight road, A, B are two mile stones such that AB = a miles. Vehicle P started from A towards B. The displacement (miles) function with time t (hours) of P is S = 5t2 + 40t. At the same time vehicle Q started from B towards A. The displacement (miles) function with time t (hours) of Q is s = 5t2 + 10t. Find the velocity of P when the vehicles cross each other. [a = 60.]
  ee
View Solution
ee  If the square of the displacement S traversed by a particle in time t is given by S2 = t2 + 7t + 49, then choose the acceleration of the particle from the following.
  ee
View Solution
ee  If the displacement function P of a particle with time t is given by P = f(t), then find the acceleration of the particle at any time t.
  ee
View Solution
ee  A particle is moving along a straight line according to the law S = 5ut - 2at2 where a > 0. Find the greatest and least velocities of the particle.  ee View Solution
ee  The velocity of a particle is related with its displacement S as V2 = 2S2 + 2kS + k2 where k is a constant. What is the acceleration of the particle when it is α units away from the starting point?  ee View Solution
ee  The displacement S of a moving particle is related with time t as S = α t2 + β t + c. The displacement of the particle after 1 sec is 40 m, its velocity and acceleration after 2 sec are 90 m/sec and 50 m/sec2. Which of the following is correct?
  ee
View Solution
ee  The distance S of a body moving along a straight line is related with its velocity v, traversed time t as S = vt + 4. What is the acceleration of the body at any time t in terms of v?
  ee
View Solution
ee  If a particle is moving according to the law V2 = (5x sin 5x + cos 7x) where V is the velocity and x is the displacement described by it, then what is the acceleration in terms of x?  ee View Solution
ee  The displacement S in metres traversed by a particle with time t in seconds is given by S = 7t2 + 8t + 4. Find the average velocity of the particle between t = 0 and t = 4.  ee View Solution
ee  A particle is moving along a straight line so that at time t, its displacement S from a fixed point in the line is given by S = 3α sin(3β t + γ) where α, β, γ are constants. If V and f are the velocity and acceleration of the particle respectively at time t, then v2 - fs = ___.
  ee
View Solution
ee  The displacement function of a particle with time t is given by S = 3αcos(5βt + γ) where α, β, γ are constants. If V and f are the velocity and acceleration of the particle respectively at time t, then dfdS = ?  ee View Solution
ee  A stone is thrown up vertically and the height S feet reached by it in time t seconds is given by S = 112t - 16t2. How much time does the stone take to reach the maximum height?
  ee
View Solution
ee  The height S feet reached in time t seconds by a stone projected vertically upwards is given by S = 128t - 16t2. What is the maximum height reached by the stone?
  ee
View Solution
ee  The displacement S covered by a particle in time t is given by S = 4kt + l where k, l are constants, then what is the acceleration of the particle at t = 6?
  ee
View Solution
ee  The displacement S of a body in t seconds is given by S = (8t3 - 4t2 + 3t + 5) m. The instantaneous velocity of the body is
  ee
View Solution
ee  The displacement 'S' described by a particle in t seconds is given by S = 2t - 2t2 ft . What is the velocity of the particle at any time t?  ee View Solution
ee  The displacement of a body with time t is related as S = ae8t - be-5t. Find the rate of change of displacement with respect to time t.  ee View Solution
ee  The displacement S (in meters) of a particle is related with time t(in seconds) as S = 3t3 + 5t2 + 4t + 3 The velocity of the particle when t = 4 sec is  ee View Solution
ee  The displacement S of a particle in time t seconds is given by S = 3t3 - 2t2 - 4t + 4 ft . What is the acceleration of the particle at time t?  ee View Solution
ee  What is the acceleration of a body at t = 3 sec whose displacement S(in metres) is related with the time as S = 3t3 - 3t2 - 3t + 5?  ee View Solution
ee  The displacement of a particle S (in metres) is related with time t (in seconds) as S = t33 -13t22 + 42t Find the acceleration of the particle when it comes to rest first time.
  ee
View Solution
ee  On a straight road, vehicle A started at a point P whose displacement (metres) function with time t (seconds) is S = 3t + 3t2. After 1sec vehicle B started from the same point P in the same direction of A. The displacement (metres) function with time t (seconds) of B is S = 6t + 12t2. What is the velocity of the vehicle B when it crosses the vehicle A?
  ee
View Solution
ee  The displacement function of a particle with time t in seconds is S = 3t3 - 5t2 + 5t + 6 ft. Find the velocity of the particle when its acceleration becomes zero.
  ee
View Solution
ee  The displacement S of a particle with respect to time t is given by S = - 3t3 + 5t. The velocity of the particle  ee View Solution
ee  The distance 'S' on a straight line traveled by a particle in time t is given by S = 3t - 5t3. What is the maximum velocity of the particle?  ee View Solution
ee  On a straight road, A, B are two mile stones such that AB = a miles. Vehicle P started from A towards B. The displacement (miles) function with time t (hours) of P is S = 3t2 + 24t. At the same time vehicle Q started from B towards A. The displacement (miles) function with time t (hours) of Q is s = 3t2 + 6t. Find the velocity of P when the vehicles cross each other. [a = 36.]
  ee
View Solution
ee  If the square of the displacement S traversed by a particle in time t is given by S2 = t2 + 9t + 64, then choose the acceleration of the particle from the following.
  ee
View Solution
ee  If the displacement function Q of a particle with time t is given by Q = f(t), then find the acceleration of the particle at any time t.
  ee
View Solution
ee  A particle is moving along a straight line according to the law S = 2ut - 9at2 where a > 0. Find the greatest and least velocities of the particle.  ee View Solution
ee  The velocity of a particle is related with its displacement S as V2 = 8S2 + 4kS + k2 where k is a constant. What is the acceleration of the particle when it is α units away from the starting point?  ee View Solution
ee  The displacement S of a moving particle is related with time t as S = α t2 + β t + c. The displacement of the particle after 1 sec is 20 m, its velocity and acceleration after 2 sec are 120 m/sec and 70 m/sec2. Which of the following is correct?
  ee
View Solution
ee  The distance S of a body moving along a straight line is related with its velocity v, traversed time t as S = vt + 8. What is the acceleration of the body at any time t in terms of v?
  ee
View Solution
ee  The displacement S in metres traversed by a particle with time t in seconds is given by S = 2t2 + 4t + 5. Find the average velocity of the particle between t = 0 and t = 5.  ee View Solution
ee  A particle is moving along a straight line so that at time t, its displacement S from a fixed point in the line is given by S = 4α sin(5β t + γ) where α, β, γ are constants. If V and f are the velocity and acceleration of the particle respectively at time t, then v2 - fs = ___.
  ee
View Solution
ee  If a particle is moving according to the law V2 = (9x sin 2x + cos 4x) where V is the velocity and x is the displacement described by it, then what is the acceleration in terms of x?  ee View Solution
ee  The displacement function of a particle with time t is given by S = 8αcos(5βt + γ) where α, β, γ are constants. If V and f are the velocity and acceleration of the particle respectively at time t, then dfdS = ?  ee View Solution
ee  A stone is thrown up vertically and the height S feet reached by it in time t seconds is given by S = 72t - 18t2. How much time does the stone take to reach the maximum height?
  ee
View Solution
ee  The height S feet reached in time t seconds by a stone projected vertically upwards is given by S = 192t - 16t2. What is the maximum height reached by the stone?
  ee
View Solution
Copyright © 1999 - 2009 HighPoints Learning Inc All rights reserved About Us | Privacy Policy | Terms & Conditions | Contact Us | Sitemap | Links
This site is best viewed with Internet Explorer 6.0 or higher.
*Test names and other trademarks are the property of the respective trademark holders.
None of the trademark holders are affiliated with HighPoints Learning or this web site.
iCoachMath :: PopUp
Enter your Mail Id: