Attempt following question by selecting a choice to answer.
B
Choose a quadratic equation that has the solutions as
(- 3 + 67)11 and
(- 3 - 67)11.cccc BBBBA.
B121
x2 - 66
x + 243 = 0
B.
B121
x2 + 66
x - 243 = 0
C.
B121
x2 + 66
x + 243 = 0
D.
B121
x2 - 66
x - 243 = 0
BB
B
Step 10: Let s1 = (- 3 + 67)11 and s2 = (- 3 - 67)11
Step 11: s1 + s2 = - 611 and s1s2 = - 243121
Step 12: Recall that: "The quadratic equation with solutions s1 and s2 is given by: x2 - (s1 + s2)x + s1s2 = 0."
Step 13: So, x2 - (s1 + s2)x + s1s2 = 0 ⇒
x2 + (611)x - (243121) = 0[Substitute the values.]
Step 14: 121x2 + 66x - 243 = 0[Multiply throughout by 121.]