Attempt following question by selecting a choice to answer.
e
What is the equation of the line that passes through the point
(3, - 54) with a slope of
45 in standard form with integer coefficients?
c eA.
e16
x + 20
y = 73
B.
e- 16
x + 20
y = 72
C.
e- 16
x + 20
y = 74
D.
e- 16
x + 20
y = - 73
e
D
Step 1: The equation of the line passing through the point (x1, y1) with slope m in point-slope form is y - y1 = m(x - x1).
Step 2: Point (x1, y1) = (3, - 54) and slope m = 45.
Step 3: y - (- 54) = 45(x - 3)[Substitute x1 = 3, y1 = - 54 and m = 45 in the equation in step 1.]
Step 4: y + 54 = 4x5 - 125[Distribute 45.]
Step 5: y = 4x5 - 7320[Subtract 54 from each side.]
Step 6: 20y = 20(4x5 - 7320)[Multiply by 20 on both sides.]
Step 7: 20y = 16x - 73 [Distribute 20.]
Step 8: - 16x + 20y = - 73 [Subtract 16x from each side.]
Step 9: The equation of the line in standard form is - 16x + 20y = - 73.