intersect as shown. Find the lengths of the two segments of the
A.
B.
C.
D.
Step 1: This problem could be solved using the geometric theorem that states: "When two chords intersect inside a circle, the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord."[
c = 2 and
d = 24.]

Step 2: Let the length of one segment of the 14 cm chord be
x cm.
Then the length of the other segment is (14 -
x) cm.
Step 3:
x(14 -
x) = 2(24)[Application of the Theorem.]
Step 4: 14
x -
x2 = 48[Distributive property.]
Step 5: 14
x -
x2 - 48 = 0
Step 6: -
x2 + 14
x - 48 = 0
Step 7:
x2 - 14
x + 48 = 0[Multiply throughout by - 1.]
Step 8: (
x - 8)(
x - 6) = 0[Factor.]
Step 9: Therefore,
x = 8, 6.
Step 10: When
x = 8, 14 -
x = 6 and if
x = 6, then 14 -
x = 8. So, the lengths of the segments of the 14 cm chord are 8 cm and 6 cm.