Attempt following question by selecting a choice to answer.
B
PQ is a line parallel to the base
BC of
ΔABC. What is the
m∠AQP, if
m∠A + m∠B = 150o?f BA.
B40
oB.
B30
oC.
B45
oD.
B50
o
B
B
Step 1: In ΔABC, m∠A + m∠B + m∠C = 180o[Since the sum of the angles in a triangle = 180o.]
Step 2: 150o + m∠C = 180o[Substitute m∠A + m∠B = 1500.]
Step 3: m∠C = 180o - 150o[Subtract 150o from each side.]
Step 4: m∠C = 30o
Step 5: In the ΔABC, PQ is parallel to BC and AC is the transversal.
Step 6: ∠AQP and ∠C are corresponding angles.
Step 7: Since, corresponding angles are congruent, m∠AQP = m∠C = 30o.
Step 8: So, m∠AQP is 30o.